document.write( "Question 357935: The measure of ∠A is 8° more than three times the measure of ∠B. If A and B are supplementary angles, find the measure of ∠A. \n" ); document.write( "
| Algebra.Com's Answer #255566 by MathTherapy(10556)     You can put this solution on YOUR website! The measure of ∠A is 8° more than three times the measure of ∠B. If A and B are supplementary angles, find the measure of ∠A.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since angle A is 8° more than three times the measure of angle B, then we can say that: A = 3B + 8, or A - 3B = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since angles A and B are supplementary angles, then we can say that: A + B = 180\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We therefore have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " A + B = 180__________eq (i) \n" ); document.write( " A - 3B = 8__________eq (ii) \n" ); document.write( "3A + 3B = 540__________eq (iii) ------ Multiplying eq (i) by 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4A = 548 ------ Adding eq (ii) & (iii)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle A = |