document.write( "Question 39958: Graph each equation. Label the vertex, focus and directrix\r
\n" ); document.write( "\n" ); document.write( "x^2-6x+10y=1
\n" ); document.write( "

Algebra.Com's Answer #25549 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2-6x%2B10y=1\"
\n" ); document.write( "\"x%5E2-6x-1=-10y\"
\n" ); document.write( "\"%28-1%2F10%29x%5E2%2B%283%2F5%29x%2B%281%2F10%29+=+y\"
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-.1x%5E2%2B0.6x%2B.1+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%280.6%29%5E2-4%2A-.1%2A.1=0.4\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=0.4 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-0.6%2B-sqrt%28+0.4+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%280.6%29%2Bsqrt%28+0.4+%29%29%2F2%5C-.1+=+-0.16227766016838\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%280.6%29-sqrt%28+0.4+%29%29%2F2%5C-.1+=+6.16227766016838\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"-.1x%5E2%2B0.6x%2B.1\" can be factored:
\n" ); document.write( " \"-.1x%5E2%2B0.6x%2B.1+=+-.1%28x--0.16227766016838%29%2A%28x-6.16227766016838%29\"
\n" ); document.write( " Again, the answer is: -0.16227766016838, 6.16227766016838.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-.1%2Ax%5E2%2B0.6%2Ax%2B.1+%29\"

\n" ); document.write( "\n" ); document.write( "You should be able to pick the information from what is above.
\n" ); document.write( "
\n" );