document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35325>Question 35325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I am having trouble with this question.  Can you help?\r<BR>\n" );
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document.write( "9^(4x-3)=4^(2x-4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25543 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This has to be solved using logarithms...so from<BR>\n" );
document.write( "9^(4x-3) = 4^(2x-4)<BR>\n" );
document.write( "take the log of both sides, apply the power rule and use your algebar tools to solve for x...here goes...<BR>\n" );
document.write( "log 9^(4x-3) = log 4^(2x-4)<BR>\n" );
document.write( "(4x-3)*log 9 = (2x-4)*log 4<BR>\n" );
document.write( "4xlog9 - 3log9 = 2xlog4 - 4log4<BR>\n" );
document.write( "4xlog9 - 2xlog4 = 3log9 - 4log4<BR>\n" );
document.write( "x(4log9 - 2log4) = 3log9 - 4log4<BR>\n" );
document.write( "x = (3log9 - 4log4) / (4log9 - 2log4) </SPAN>\n" );
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