document.write( "Question 357758: The length of a rectangle is three feet shorter than twice its width. If the are of a rectangle is 170ft^2, what is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #255412 by mananth(16946)\"\" \"About 
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The length of a rectangle is three feet shorter than twice its width. If the are of a rectangle is 170ft^2, what is the length of the rectangle?\r
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\n" ); document.write( "let width be x feet
\n" ); document.write( "length = 2x-3
\n" ); document.write( "Area = 170 ft^2
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\n" ); document.write( "Area = L*W
\n" ); document.write( "x(2x-3)=170
\n" ); document.write( "2x^2-3x=170
\n" ); document.write( "2x^2-3x-170 =0
\n" ); document.write( "2x^2-20x+17x-170=0
\n" ); document.write( "2x(x-10)+17(x-10)=0
\n" ); document.write( "(x-10)(2x+17)=0
\n" ); document.write( "Take positive value x= 10 feetthe width
\n" ); document.write( "Length = 20-3 = 17 feet
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\n" ); document.write( "m.ananth@hotmail.ca
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