document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=357793>Question 357793</A>: <I><SPAN STYLE=\"word-break: break-all;\"> greg has two soulutions avaiable in a lAB, one with 6% alcohol and another with 14% alcohol. how much of each should he mix together to obtain 10 gallons of a solution hat contains 12% alcohol. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #255381 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=255381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one with 6% alcohol : let this be x gallons<BR>\n" );
document.write( "another with 14% alcohol. this will be 10-x gallons<BR>\n" );
document.write( "mix 10 gallons  12% alcohol.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "6x+14(10-x)=10*12<BR>\n" );
document.write( "6x+140-14x=120<BR>\n" );
document.write( "-8x=-20<BR>\n" );
document.write( "x=2.5 gallons 6% alcohol<BR>\n" );
document.write( "7.5 gallons 14% alcohol<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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