document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=357722>Question 357722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this equation: 2 planes which are 1,220 miles apart fly towards eachother, their speeds differ by 60 mph. If they each pass eachother in 2 hours, what is the speed of each plane? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #255363 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=255363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> plane A speed = x mph<BR>\n" );
document.write( "plane B speed = x+60 mph<BR>\n" );
document.write( "since they are travelling towards each other the effective speed will be 2x+60 mph<BR>\n" );
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document.write( "distance apart 1220 miles<BR>\n" );
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document.write( "time they cross = 2 hours<BR>\n" );
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document.write( "time = distance / speed<BR>\n" );
document.write( "1220/2x+60 =2<BR>\n" );
document.write( "1220 =2*(2x+60)<BR>\n" );
document.write( "1220=4x+120<BR>\n" );
document.write( "1220-120=4x<BR>\n" );
document.write( "1100=4x<BR>\n" );
document.write( "x=1100/4<BR>\n" );
document.write( "x=275 mph speed of plane A<BR>\n" );
document.write( "Plane B speed = 275+60 = 335 mph </SPAN>\n" );
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