document.write( "Question 357687: how much 60% solution must be mixed with a 80% solution to produce 25 gallons of a 76% solution \n" ); document.write( "
Algebra.Com's Answer #255336 by mananth(16946)\"\" \"About 
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how much 60% solution let it be x gallons
\n" ); document.write( " 80% solution 25-x
\n" ); document.write( "mix gallons of a 76% solution--- 25
\n" ); document.write( "..
\n" ); document.write( "0.6x+0.8(25-x)=0.76*25
\n" ); document.write( "0.6x+20-0.8x=19
\n" ); document.write( "-0.2x=-1
\n" ); document.write( "x=-1/-0.2
\n" ); document.write( "x= 5 gallons of 60% solution has to be added.
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\n" ); document.write( "m.ananth@hotmail.ca
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