document.write( "Question 357687: how much 60% solution must be mixed with a 80% solution to produce 25 gallons of a 76% solution \n" ); document.write( "
Algebra.Com's Answer #255336 by mananth(16946)![]() ![]() You can put this solution on YOUR website! how much 60% solution let it be x gallons \n" ); document.write( " 80% solution 25-x \n" ); document.write( "mix gallons of a 76% solution--- 25 \n" ); document.write( ".. \n" ); document.write( "0.6x+0.8(25-x)=0.76*25 \n" ); document.write( "0.6x+20-0.8x=19 \n" ); document.write( "-0.2x=-1 \n" ); document.write( "x=-1/-0.2 \n" ); document.write( "x= 5 gallons of 60% solution has to be added. \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |