document.write( "Question 357522: A new game show requires a playing field with a perimeter of 54 yards and length 3 yards less than twice the width. What are the demensions? \n" ); document.write( "
Algebra.Com's Answer #255288 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-3 \n" ); document.write( "2L+2W=54 \n" ); document.write( "2(2W-3)+2W=54 \n" ); document.write( "4W-6+2W=54 \n" ); document.write( "6W=54+6 \n" ); document.write( "6W=60 \n" ); document.write( "W=60/6 \n" ); document.write( "W=10 ANS. FOR THW WIDTH. \n" ); document.write( "L=2*10-3=20-3=17 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*17+2*10=54 \n" ); document.write( "34+20=54 \n" ); document.write( "54=54 \n" ); document.write( " |