document.write( "Question 357522: A new game show requires a playing field with a perimeter of 54 yards and length 3 yards less than twice the width. What are the demensions? \n" ); document.write( "
Algebra.Com's Answer #255288 by checkley77(12844)\"\" \"About 
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L=2W-3
\n" ); document.write( "2L+2W=54
\n" ); document.write( "2(2W-3)+2W=54
\n" ); document.write( "4W-6+2W=54
\n" ); document.write( "6W=54+6
\n" ); document.write( "6W=60
\n" ); document.write( "W=60/6
\n" ); document.write( "W=10 ANS. FOR THW WIDTH.
\n" ); document.write( "L=2*10-3=20-3=17 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*17+2*10=54
\n" ); document.write( "34+20=54
\n" ); document.write( "54=54
\n" ); document.write( "
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