document.write( "Question 357440: how much of an alloy that is 30% should be mixed with 500 ounces of an alloy that is 70% copper in order to get an alloy that is 50% copper \n" ); document.write( "

Algebra.Com's Answer #255281 by scott8148(6628) $\"\"$ $\"About$

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(x)(30%) + (500)(70%) = (500 + x)(50%) \n" ); document.write( "

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