document.write( "Question 357520: Sally is ten years younger than Mary. Ten years ago, Sally was half as old as Mary was then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #255274 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "*Note: Sally always has been (and will be) 10 years younger than Mary
\n" ); document.write( "Let x represent Marys age. then Sally's age would be(x-10)
\n" ); document.write( "Ten years ago***
\n" ); document.write( "(x-10) = x/2
\n" ); document.write( "2(x-10)= x
\n" ); document.write( "2x - 20 = x
\n" ); document.write( "x = 20 Mary's age 10 year ago(Sally was 10 then)\r
\n" ); document.write( "\n" ); document.write( "Presently Mary is now 30 and Sally is 20\r
\n" ); document.write( "\n" ); document.write( "checking our answer
\n" ); document.write( "10 = 20/2 \n" ); document.write( "
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