document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40099>Question 40099</A>: <I><SPAN STYLE=\"word-break: break-all;\">   Could you help me with this problem?<BR>\n" );
document.write( "  Find the area of the shaded part .  It's a square with a circle in the middle.<BR>\n" );
document.write( "  The circle is not shaded, Use 3.14 for pi and round your answer to one decimal place.<BR>\n" );
document.write( "  Thank you,<BR>\n" );
document.write( "   Sher </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25527 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well without providing the radius, I'll give you the general solution...if the circle is inside the square and has a radius of r, the side of the square is 2r.<BR>\n" );
document.write( "Thus the square's area is 4r^2, and the area of the circle is (pi)r^2.  Just subtract the two to find the shaded area of the square not contained in the circle...<BR>\n" );
document.write( "(4-(pi))r^2<BR>\n" );
document.write( "Just plug in whatever r you have and get the answer... </SPAN>\n" );
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