document.write( "Question 357404: Hi
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document.write( " Stuck on a particular problem
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document.write( "Question
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document.write( "Find the values of x for which\r
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document.write( "i) 3x-5>x+13
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document.write( "ii) x^2-4x-12>0\r
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document.write( "Would appreciate any help \n" );
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Algebra.Com's Answer #255258 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! i) 3x - 5 > x + 13 \n" ); document.write( "Add 5 to both sides, eliminates -5 on the left \n" ); document.write( "3x > x + 13 + 5 \n" ); document.write( "Subtract x from both sides \n" ); document.write( "3x - x > 18 \n" ); document.write( "2x > 18 \n" ); document.write( "divide both sides by 2 \n" ); document.write( "x > \n" ); document.write( "x > 9 \n" ); document.write( ": \n" ); document.write( "ii) x^2 - 4x - 12 > 0 \n" ); document.write( "Factors to \n" ); document.write( "(x-6)(x+2) > 0 \n" ); document.write( "x > 6; expression greater than 0 above +6 \n" ); document.write( "x < -2; expression is greater than 0 below -2 \n" ); document.write( ": \n" ); document.write( "Graphically, this can be seen \n" ); document.write( " |