document.write( "Question 357341: A 490m piece of rope is cut into three pieces. The first piece is three times the second. The third is 23 less than the first. How long are the pieces?
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Algebra.Com's Answer #255192 by checkley77(12844)\"\" \"About 
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F=3S
\n" ); document.write( "T=F-23
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\n" ); document.write( "F+S+T=490
\n" ); document.write( "(3S)+S+(3S-23)=490
\n" ); document.write( "7S=490+23
\n" ); document.write( "7S=513
\n" ); document.write( "S=513/7
\n" ); document.write( "S=73.286 IS THE SECOND PIECE.
\n" ); document.write( "F=3*73.286=219.857 IS THE FIRST PIECE.
\n" ); document.write( "T=219.857-234=196.857 IS THE THIRD PIECE.
\n" ); document.write( "PROOF:
\n" ); document.write( "219.857+73.286+196.857=490
\n" ); document.write( "490=490
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