document.write( "Question 357329: The length of a rectangle is twice the width. if the length is increased by 4 inches and the width is decreased by 1 inch, a new rectangle is formed whose perimeter is 198 inches. find the dimesions of the originional rectangle \n" ); document.write( "

Algebra.Com's Answer #255189 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let w represent te original width.  Than 2w will be the original length
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document.write( "2*l + 2*w = P (all the way around the rectangle)
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document.write( "2*(2w+ 4\")+ 2( w- 1\") = 198\"
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document.write( "simplify ans Solve
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document.write( "4w + 8 + 2w -2 = 198\"
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document.write( "6w = 192\"
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document.write( "w = 32\"
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document.write( "Original triangle was 32\" wide and 64\" long
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document.write( "check your answer
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document.write( "2*68 + 2* 31 = 198 \n" );
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