document.write( "Question 357317: one grade of tes, worth $3.20 per pound, is to be mixed with another grade worth $2.00 per pound to make 20 pounds that will sell for $2.72 per pound. how many pounds of the $3.20 tea must be used? and how many pounds of the $2.00 tea must be used? \n" ); document.write( "

Algebra.Com's Answer #255182 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x be the amount of the $3.20/lb grade.  Then (20-x) would be the amount of the $2.00/lb tea.
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document.write( "$3.20*x + $2.00(20 - x) = $2.72*20lb
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document.write( "simplify and Solve
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document.write( "$3.20*x + $2.00*20 - 2.00x =$2.72*20lb
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document.write( "$1.20*x  = $2.72*20lb - $2.00*20
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document.write( "$1.20*x  = .72*20lb = 14.4
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document.write( "x = 12lb
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document.write( "the amount of the $2.00 tea would be 8 lb
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document.write( "check your answer
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document.write( "3.20*12  + 2.00*8 = 38.4 + 16 = 2.72*20 = 54.40 \n" );
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