document.write( "Question 357316: some guy rowed 18 miles down the delaware river in two hours but the return trip took him four and a half hours find the rate this guy can row in still water and find the rate of the current \r
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document.write( "Let X = rate guy can row in still water
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document.write( "Let Y = rate of current\r
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document.write( "D = r . T \r
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document.write( "Down stream x plus y
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document.write( "upstream x - y \n" );
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Algebra.Com's Answer #255180 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Downstream speed = 18/2 = 9 mph \n" ); document.write( "Upstream = 18/4.5 = 4 mph \n" ); document.write( "-------- \n" ); document.write( "Rowing speed = the average = (9+4)/2 = 6.5 mph \n" ); document.write( "Current = the difference = 9 - 6.5 = 2.5 mph \n" ); document.write( " \n" ); document.write( " |