document.write( "Question 357316: some guy rowed 18 miles down the delaware river in two hours but the return trip took him four and a half hours find the rate this guy can row in still water and find the rate of the current \r
\n" ); document.write( "\n" ); document.write( "Let X = rate guy can row in still water
\n" ); document.write( "Let Y = rate of current\r
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\n" ); document.write( "\n" ); document.write( "D = r . T \r
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\n" ); document.write( "\n" ); document.write( "Down stream x plus y
\n" ); document.write( "upstream x - y
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Algebra.Com's Answer #255180 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Downstream speed = 18/2 = 9 mph
\n" ); document.write( "Upstream = 18/4.5 = 4 mph
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\n" ); document.write( "Rowing speed = the average = (9+4)/2 = 6.5 mph
\n" ); document.write( "Current = the difference = 9 - 6.5 = 2.5 mph
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