document.write( "Question 357287: A boy cycles from his house to a friend's house at 20 km/h and home again 25km/h. If his round trip takes 9/10 of an hour, how far is it to his friend's house?\r
\n" );
document.write( "\n" );
document.write( "I need the working out steps \r
\n" );
document.write( "\n" );
document.write( "thank you \n" );
document.write( "
Algebra.Com's Answer #255158 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the distance be x km \n" ); document.write( "time forward = x/20 hours \n" ); document.write( "... \n" ); document.write( "time return = x/25 hours \n" ); document.write( "... \n" ); document.write( "x/20 + x/25 = 9/10 \n" ); document.write( "... \n" ); document.write( "(5x+4x) / 100 = 9/10 \n" ); document.write( "9x/100 = 9/10 \n" ); document.write( "90x= 900 \n" ); document.write( "x=10 km distance to friend's house\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |