document.write( "Question 357287: A boy cycles from his house to a friend's house at 20 km/h and home again 25km/h. If his round trip takes 9/10 of an hour, how far is it to his friend's house?\r
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\n" ); document.write( "\n" ); document.write( "thank you
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Algebra.Com's Answer #255158 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let the distance be x km
\n" ); document.write( "time forward = x/20 hours
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\n" ); document.write( "time return = x/25 hours
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\n" ); document.write( "x/20 + x/25 = 9/10
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\n" ); document.write( "(5x+4x) / 100 = 9/10
\n" ); document.write( "9x/100 = 9/10
\n" ); document.write( "90x= 900
\n" ); document.write( "x=10 km distance to friend's house\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
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