document.write( "Question 40082: can you help me?
\n" ); document.write( "find the illegal values of c in the multiplcation statement \"%28c%5E2-3c-10%29%2F%28c%5E2%2B5c-14%29\"*\"%28c%5E2-c-2%29%2F%28c%5E2-2c-15%29\"
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Algebra.Com's Answer #25509 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Once again, denominators cannot be zero, so we have to see what values of c make that so...those values are the \"illegal\" ones...so for
\n" ); document.write( "c^2 + 5c - 14 = 0
\n" ); document.write( "(c+7)(c-2) = 0
\n" ); document.write( "c = -7 or c = 2 and for
\n" ); document.write( "c^2 - 2c - 15 = 0
\n" ); document.write( "(c-5)(c+3) = 0
\n" ); document.write( "c = 5 or c = -3
\n" ); document.write( "Thus c is not allowed to be any of
\n" ); document.write( "-7, 2, 5, or -3
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