document.write( "Question 357097: The larger of two numbers is 8 times the smaller. If the larger number exceeds the smaller by 56, find the numbers. \n" ); document.write( "

Algebra.Com's Answer #255084 by neatmath(302) $\"\"$ $\"About$

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Let x be the larger number, and y be the smaller number. We know:
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\n" ); document.write( "\n" ); document.write( " $\"x=8y\"$ and
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\n" ); document.write( "\n" ); document.write( " $\"x=y%2B56\"$
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\n" ); document.write( "\n" ); document.write( "So, we can solve this system of equations by:
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\n" ); document.write( "\n" ); document.write( " $\"8y=y%2B56\"$ substituting
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\n" ); document.write( "\n" ); document.write( " $\"7y=56\"$
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\n" ); document.write( "\n" ); document.write( " $\"y=8\"$
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\n" ); document.write( "\n" ); document.write( "Thus
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\n" ); document.write( "\n" ); document.write( " $\"x=8%2A8\"$
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\n" ); document.write( "\n" ); document.write( " $\"x=64\"$
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\n" ); document.write( "\n" ); document.write( "The two numbers are 64 and 8.
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\n" ); document.write( "\n" ); document.write( "I hope this helps!
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