document.write( "Question 357125: If the sum of ages of three friends is 126.The ratio of ages of John and Maria is 4:3 and that of John and Linda is 5:7.Find the age of John? \n" ); document.write( "
Algebra.Com's Answer #255079 by checkley77(12844)\"\" \"About 
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LET X=JOHN'S AGE
\n" ); document.write( "LET Y=MARIA'S AGE
\n" ); document.write( "LET Z=LINDA'S AGE.
\n" ); document.write( "X/Y=4/3
\n" ); document.write( "4Y=3X
\n" ); document.write( "Y=3X/4
\n" ); document.write( "X/Z=5/7
\n" ); document.write( "5Z=7X
\n" ); document.write( "Z=7X/5
\n" ); document.write( "X+Y+Z=126
\n" ); document.write( "X+(3X/4)+(7X/5)=126
\n" ); document.write( "(20X+5*3X+4*7X)/4*5=126
\n" ); document.write( "(20X+15X+28X)/20=126
\n" ); document.write( "63X=20*126
\n" ); document.write( "63X=2,250
\n" ); document.write( "X=2,520/63
\n" ); document.write( "X=40 AGE OF JOHN.
\n" ); document.write( "4Y=3*40
\n" ); document.write( "4Y=120
\n" ); document.write( "Y=120/40=30 AGE OF MARIA.
\n" ); document.write( "5Z=7*40
\n" ); document.write( "5Z=280
\n" ); document.write( "Z=280/5=56 AGE OF LINDA.
\n" ); document.write( "PROOF:
\n" ); document.write( "40+30+56=126
\n" ); document.write( "126=126
\n" ); document.write( " \n" ); document.write( "
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