document.write( "Question 357136: A chemist wants to make 54 mL of a 17% acid solution by mixing a 13% acid solution and an 19% acid solution. How many milliliters of each solution should the chemist use? \r
\n" );
document.write( "\n" );
document.write( "13% solution ? mL
\n" );
document.write( "19% solution ? mL \n" );
document.write( "
Algebra.Com's Answer #255070 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! ,19X+.13(54-X)=.17*54 \n" ); document.write( ".19X+7.02-.13X=9.18 \n" ); document.write( ".06X=9.18-7.02 \n" ); document.write( ".06X=2.16 \n" ); document.write( "X=2.16/.06 \n" ); document.write( "X=36 mL OF THE 19% SOLUTION IS USED. \n" ); document.write( "54-36=18 mL OF THE 13 % SOLUTION IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".19*36+.13*18=.17*54 \n" ); document.write( "6.84+2.34=9.18 \n" ); document.write( "9.18=9.18 \n" ); document.write( " |