document.write( "Question 357136: A chemist wants to make 54 mL of a 17% acid solution by mixing a 13% acid solution and an 19% acid solution. How many milliliters of each solution should the chemist use? \r
\n" ); document.write( "\n" ); document.write( "13% solution ? mL
\n" ); document.write( "19% solution ? mL
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Algebra.Com's Answer #255070 by checkley77(12844)\"\" \"About 
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,19X+.13(54-X)=.17*54
\n" ); document.write( ".19X+7.02-.13X=9.18
\n" ); document.write( ".06X=9.18-7.02
\n" ); document.write( ".06X=2.16
\n" ); document.write( "X=2.16/.06
\n" ); document.write( "X=36 mL OF THE 19% SOLUTION IS USED.
\n" ); document.write( "54-36=18 mL OF THE 13 % SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".19*36+.13*18=.17*54
\n" ); document.write( "6.84+2.34=9.18
\n" ); document.write( "9.18=9.18
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