document.write( "Question 357149: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train B is traveling at 104 miles per hour. Train A passes a station at 11:10 am. If train B passes the same station at 11:40 am at what time will train B catch up to train A
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\n" ); document.write( "\n" ); document.write( "Can some one please help me. Not sure on how to set up the equation
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Algebra.Com's Answer #255062 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "BECAUSE THE DISTANCES WILL BE EQUAL WE HAVE:
\n" ); document.write( "D=100T FOR TRAIN A.
\n" ); document.write( "D=104(T-.5) FOR TRAIN B.
\n" ); document.write( "100T=104(T-.5)
\n" ); document.write( "100T=104T-52
\n" ); document.write( "100T-104T=-52
\n" ); document.write( "-4T=-52
\n" ); document.write( "T=-52/-4
\n" ); document.write( "T=13 HOURS OR @ 12:10 AM. THE NEXT MORNING THEY WILL MEET.
\n" ); document.write( "PROOF:
\n" ); document.write( "100*13=104(13-.5)
\n" ); document.write( "1,300=104*12.5
\n" ); document.write( "1,300=1,300 MILES TRAVELED.
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