document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38795>Question 38795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem, if i do not get this problem right i will fail and have to repeat my senior year at my school 6x+18/x^2-9 divided by x+3/x-3 mutilplied by x+3/6 = ?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "sincerely:: failure in math </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25506 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay...first of all, the fact that you care makes you Not A Failure...now on to the problem...let us factor everything first...<BR>\n" );
document.write( "6x+18/x^2-9 divided by x+3/x-3 multiplied by x+3/6 becomes<BR>\n" );
document.write( "6(x+3) / (x+3)(x-3) divided by x+3/x-3 multiplied by x+3/6<BR>\n" );
document.write( "now invert the second one and multiply and get<BR>\n" );
document.write( "[6(x+3) / (x+3)(x-3)] * (x-3)/(x+3) * (x+3)/6<BR>\n" );
document.write( "Now look what cancels...the 6's, two pairs of (x+3), and the pair of (x-3),<BR>\n" );
document.write( "leaving the remarkable answer.....<BR>\n" );
document.write( "1  !!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );