document.write( "Question 357157: a person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. how many of each coin does the person have? \n" ); document.write( "
Algebra.Com's Answer #255057 by checkley77(12844) ![]() You can put this solution on YOUR website! D=Q+7 \n" ); document.write( ".25Q+.10D=2.80 \n" ); document.write( ".25Q+.10(Q+7)=2.80 \n" ); document.write( ".25Q+10Q+.70=2.80 \n" ); document.write( ".35Q=2.80-.70 \n" ); document.write( ".35Q=2.10 \n" ); document.write( "Q=2.10/.35 \n" ); document.write( "Q=6 QUARTERS. \n" ); document.write( "D=6+7=13 DIMES. \n" ); document.write( "PROOF: \n" ); document.write( ".25*6+.10*13=2.80 \n" ); document.write( "1.50+1.30=2.80 \n" ); document.write( "2.80=2.80 \n" ); document.write( " |