document.write( "Question 357157: a person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. how many of each coin does the person have? \n" ); document.write( "
Algebra.Com's Answer #255057 by checkley77(12844)\"\" \"About 
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D=Q+7
\n" ); document.write( ".25Q+.10D=2.80
\n" ); document.write( ".25Q+.10(Q+7)=2.80
\n" ); document.write( ".25Q+10Q+.70=2.80
\n" ); document.write( ".35Q=2.80-.70
\n" ); document.write( ".35Q=2.10
\n" ); document.write( "Q=2.10/.35
\n" ); document.write( "Q=6 QUARTERS.
\n" ); document.write( "D=6+7=13 DIMES.
\n" ); document.write( "PROOF:
\n" ); document.write( ".25*6+.10*13=2.80
\n" ); document.write( "1.50+1.30=2.80
\n" ); document.write( "2.80=2.80
\n" ); document.write( "
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