document.write( "Question 357126: Hello, tutors,
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\n" ); document.write( "\n" ); document.write( "a spherical weather balloon needs to hold at least 175 cubic feet of helium to be buoyant enough to lift the meteorogical instruments. will a helium-filled balloon with a diameter of 8 feet stay aloft?\r
\n" ); document.write( "\n" ); document.write( "What should I solve this problem? The volume? Please let me know the process about this.
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Algebra.Com's Answer #255033 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, let's find the actual approximate volume of the sphere with a diameter of 8 ft. Since the diameter is 8 feet, the radius is \"r=d%2F2=8%2F2=4\" feet. So \"r=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"V=%284%2F3%29pi%2Ar%5E3\" Start with the volume of a sphere formula.\r
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\n" ); document.write( "\n" ); document.write( "\"V=%284%2F3%29pi%2A%284%29%5E3\" Plug in \"r=4\".\r
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\n" ); document.write( "\n" ); document.write( "\"V=%284%2F3%29%283.14159265%29%2A%284%29%5E3\" Replace \"pi\" with \"3.14159265\" (note: Use more digits of \"pi\" to get better accuracy).\r
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\n" ); document.write( "\n" ); document.write( "\"V=%284%2F3%29%283.14159265%29%2A%2864%29\" Cube \"4\" to get \"64\".\r
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\n" ); document.write( "\n" ); document.write( "\"V=%284%2F3%29%28201.0619296%29\" Multiply \"3.14159265\" and \"64\" to get \"201.0619296\" (this figure is approximate).\r
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\n" ); document.write( "\n" ); document.write( "\"V=268.0825728\" Multiply \"4%2F3\" and \"201.0619296\" to get \"268.0825728\" (again, this figure is approximate).\r
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\n" ); document.write( "\n" ); document.write( "So the approximate volume is 268.0825728 cubic feet which is definitely larger than 175 cubic feet.\r
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\n" ); document.write( "\n" ); document.write( "So the balloon will stay aloft.
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