document.write( "Question 357069: P(E and F) =.21
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Algebra.Com's Answer #255006 by edjones(8007)\"\" \"About 
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P(EnF) = .21 Intersection of E and F
\n" ); document.write( "P(E) = .4
\n" ); document.write( "P(F|E)= .21/.4 = .525 Probability of F in E.
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