document.write( "Question 357069: P(E and F) =.21
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document.write( "p(E) = .4
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document.write( "what is P(F/E) \n" );
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Algebra.Com's Answer #255006 by edjones(8007)![]() ![]() You can put this solution on YOUR website! P(EnF) = .21 Intersection of E and F \n" ); document.write( "P(E) = .4 \n" ); document.write( "P(F|E)= .21/.4 = .525 Probability of F in E. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |