document.write( "Question 357075: At precisely noon, one plane leaves New York, heading for Orlando, and another leaves Orlando, heading for New York. The distance from New York to Orlando is 1300 mi. The plane from New York flies at 450 mph and the Orlando plane flies at 490 mph. When will the planes be 125 mi apart?
\n" ); document.write( "And this is what I got:
\n" ); document.write( "450x+490x=125
\n" ); document.write( "940x=125
\n" ); document.write( "x=125/940
\n" ); document.write( "x=25/188 <-I'm stuck at right here.
\n" ); document.write( "Thank you in advance!! \n" ); document.write( "
Algebra.Com's Answer #255001 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
At precisely noon, one plane leaves New York, heading for Orlando, and another
\n" ); document.write( "leaves Orlando, heading for New York.
\n" ); document.write( "The distance from New York to Orlando is 1300 mi.
\n" ); document.write( " The plane from New York flies at 450 mph and the Orlando plane flies at 490 mph.
\n" ); document.write( " When will the planes be 125 mi apart?
\n" ); document.write( ":
\n" ); document.write( "And this is what I got:
\n" ); document.write( "I think what you want here is:
\n" ); document.write( "450x + 490x = 1300 - 125
\n" ); document.write( "940x = 1175
\n" ); document.write( "x = \"1175%2F940\"
\n" ); document.write( "x = 1.25 hrs or 1 hr 15 min they will 125 mi apart
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "You can prove this
\n" ); document.write( "1.25(450) = 562.5 mi
\n" ); document.write( "1.25(490) = 612.5 mi
\n" ); document.write( "-------------------
\n" ); document.write( "total dist: 1175, leaving 125 mi left to be 1300 mi \n" ); document.write( "
\n" );