document.write( "Question 357055: I need help to assist my 7th grader.\r
\n" ); document.write( "\n" ); document.write( "How to set up ratio....\r
\n" ); document.write( "\n" ); document.write( "Phone Plan 1 is $.18 per minute
\n" ); document.write( "Phone Plan 2 is $50 base plan and $.10 per minute.\r
\n" ); document.write( "\n" ); document.write( "At what point is it cheaper to use plan 1?\r
\n" ); document.write( "\n" ); document.write( "How do I show her how to do this?
\n" ); document.write( "

Algebra.Com's Answer #254984 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Let m = minutes used
\n" ); document.write( ".
\n" ); document.write( "Phone Plan 1 is $.18 per minute
\n" ); document.write( "cost of plan 1 = .18m
\n" ); document.write( ".
\n" ); document.write( "Phone Plan 2 is $50 base plan and $.10 per minute.
\n" ); document.write( "cost of plan 2 = .10m + 50
\n" ); document.write( ".
\n" ); document.write( "At what point is it cheaper to use plan 1?
\n" ); document.write( "\"cost of plan 1\" < \"cost of plan 2\"
\n" ); document.write( ".18m < .10m + 50
\n" ); document.write( "subtracting .10m from both sides:
\n" ); document.write( ".08m < 50
\n" ); document.write( "dividing both sides by .08
\n" ); document.write( "m < 50/.08
\n" ); document.write( "m < 625 minutes
\n" ); document.write( ".
\n" ); document.write( "Therefore:
\n" ); document.write( "At what point is it cheaper to use plan 1?
\n" ); document.write( "when minutes used is less than 625 minutes
\n" ); document.write( "
\n" );