document.write( "Question 357020: A passenger train travels 295 mi in the same amount of time it takes a freight train to travel 225 mi. The rate of the passenger train is 14mph greater than the rate of the freight train. Find the rate of each train. \n" ); document.write( "
Algebra.Com's Answer #254968 by mananth(16946)![]() ![]() You can put this solution on YOUR website! speed of freight train =x \n" ); document.write( "passanger train speed = x+14 \n" ); document.write( "... \n" ); document.write( "passanger train distance = 295 \n" ); document.write( "freight train distance = 225 \n" ); document.write( "... \n" ); document.write( "Time = distance/speed \n" ); document.write( "both take same time \n" ); document.write( "295/x+14 = 225/x \n" ); document.write( "295x=225(x+14) \n" ); document.write( "295x-225x= 3150 \n" ); document.write( "70x=3150 \n" ); document.write( "x= 45 mph speed of freight train \n" ); document.write( "passanger train speed = 45+14 = 59 mph \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |