document.write( "Question 357020: A passenger train travels 295 mi in the same amount of time it takes a freight train to travel 225 mi. The rate of the passenger train is 14mph greater than the rate of the freight train. Find the rate of each train. \n" ); document.write( "
Algebra.Com's Answer #254968 by mananth(16946)\"\" \"About 
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speed of freight train =x
\n" ); document.write( "passanger train speed = x+14
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\n" ); document.write( "passanger train distance = 295
\n" ); document.write( "freight train distance = 225
\n" ); document.write( "...
\n" ); document.write( "Time = distance/speed
\n" ); document.write( "both take same time
\n" ); document.write( "295/x+14 = 225/x
\n" ); document.write( "295x=225(x+14)
\n" ); document.write( "295x-225x= 3150
\n" ); document.write( "70x=3150
\n" ); document.write( "x= 45 mph speed of freight train
\n" ); document.write( "passanger train speed = 45+14 = 59 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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