document.write( "Question 357019: The sum of the sqaures of two consecutive odd numbers is 202, what are the numbers? Show equation \n" ); document.write( "
Algebra.Com's Answer #254967 by mananth(16946)\"\" \"About 
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let the numbers be x & x+2
\n" ); document.write( "x^2 +(x+2)^2 =202
\n" ); document.write( "x^2+x^2+4x+4=202
\n" ); document.write( "2x^2+4x-198=0
\n" ); document.write( "/2
\n" ); document.write( "x^2+2x-99=0
\n" ); document.write( "x^2+11x-9x-99=0
\n" ); document.write( "x(x+11)-9(x+11)=0
\n" ); document.write( "(x+11)(x-9)=0
\n" ); document.write( "the numbers are 9,11
\n" ); document.write( "-11,-9
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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