document.write( "Question 357019: The sum of the sqaures of two consecutive odd numbers is 202, what are the numbers? Show equation \n" ); document.write( "
Algebra.Com's Answer #254967 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the numbers be x & x+2 \n" ); document.write( "x^2 +(x+2)^2 =202 \n" ); document.write( "x^2+x^2+4x+4=202 \n" ); document.write( "2x^2+4x-198=0 \n" ); document.write( "/2 \n" ); document.write( "x^2+2x-99=0 \n" ); document.write( "x^2+11x-9x-99=0 \n" ); document.write( "x(x+11)-9(x+11)=0 \n" ); document.write( "(x+11)(x-9)=0 \n" ); document.write( "the numbers are 9,11 \n" ); document.write( "-11,-9 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |