document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=357004>Question 357004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An accurate clock shows exactly 3 pm. In how many minutes will the minute hand<BR>\n" );
document.write( "catch up with the hour hand? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254946 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # minute spaces traveled by the minute hand.  Then x/12 = # minute spaces traveled by the hour hand.  At the initial time of 3pm, the minute hand and the hour hand are separated by 15 minute spaces. This means that<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+15+%2B+x%2F12 ALIGN=MIDDLE  ALT=\"x+=+15+%2B+x%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=11x%2F12+=+15 ALIGN=MIDDLE  ALT=\"11x%2F12+=+15\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+16.36 ALIGN=MIDDLE  ALT=\"x+=+16.36\"   DISABLED_style= \"max-width:90%; height:auto;\" >, to 2 decimal places. Therefore the clock hands will be together at 3:16, 22 seconds, pm. </SPAN>\n" );
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