document.write( "Question 356975: solve
\n" ); document.write( "\"sqrt%28y%2B4%29%2B6=7\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2Bsqrt%28z-6%29=sqrt%28z%2B9%29\"
\n" ); document.write( "

Algebra.Com's Answer #254913 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28y%2B4%29%2B6=7\"
\n" ); document.write( "\"sqrt%28y%2B4%29=1\". Squaring both sides tyo eliminate the radical,
\n" ); document.write( "\"y%2B4=1\",
\n" ); document.write( "\"y+=+-3\". This value satisfies the original equation, so this is the final answer.
\n" ); document.write( "\"3%2Bsqrt%28z-6%29=sqrt%28z%2B9%29\".
\n" ); document.write( "Squaring both sides, \"9+%2B+6%2Asqrt%28z-6%29+%2Bz-6+=+z%2B9\",
\n" ); document.write( "\"3%2B6%2Asqrt%28z-6%29+=+9\",
\n" ); document.write( "\"6%2Asqrt%28z-6%29+=+6\",
\n" ); document.write( "\"sqrt%28z-6%29+=+1\",
\n" ); document.write( "\"z-6=1\",
\n" ); document.write( "\"z=7\". This value satisfies the original equation, so this is the final answer.
\n" ); document.write( "
\n" ); document.write( "
\n" );