document.write( "Question 356917: A chemist has two large containers of salt solution. The concentration of the salt is different in the two containers. She blends 80mL of the first solution with 320 mL of the second solution to obtain a solution with concentration 56g/mL. She blends 300 mL of the first solution with 200 mL of the second solution to obtain a solution with concentration 48g/mL. What are the concentrations of the original solutions. \n" ); document.write( "

Algebra.Com's Answer #254902 by robertb(5830) $\"\"$ $\"About$

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Let x = concentration, in g/mL of the first salt solution.
\n" ); document.write( "Let y = concentration, in g/mL of the second salt solution.
\n" ); document.write( "Then the pertinent equations are:
\n" ); document.write( "80x + 320y = 56*400 = 22,400, and
\n" ); document.write( "300x + 200y = 48*500 = 24,000.
\n" ); document.write( "solving the system simultaneously, we get x = 40 g/mL, and y = 60 g/mL.
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