document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356917>Question 356917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two large containers of salt solution.  The concentration of the salt is different in the two containers.  She blends 80mL of the first solution with 320 mL of the second solution to obtain a solution with concentration 56g/mL.  She blends 300 mL of the first solution with 200 mL of the second solution to obtain a solution with concentration 48g/mL.  What are the concentrations of the original solutions.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254901 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has two large containers of salt solution.  The concentration of the salt is different in the two containers.  She blends 80mL of the first solution with 320 mL of the second solution to obtain a solution with concentration 56g/mL.  She blends 300 mL of the first solution with 200 mL of the second solution to obtain a solution with concentration 48g/mL.  What are the concentrations of the original solutions.  <BR>\n" );
document.write( "Solution A concentration be x%<BR>\n" );
document.write( "solution B concentration be y%<BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.8x+3.2y=400*0.56<BR>\n" );
document.write( "0.8x+3.2y= 224<BR>\n" );
document.write( "multiply by 10<BR>\n" );
document.write( "8x+32y=2240....................1<BR>\n" );
document.write( "3x+2y= 240......................2<BR>\n" );
document.write( "multiply by -16 and add to first equation<BR>\n" );
document.write( "-48x-32y=-3840<BR>\n" );
document.write( "add<BR>\n" );
document.write( "-40x=-1600<BR>\n" );
document.write( "x= 40% solution A<BR>\n" );
document.write( "plug value of x in equation 2<BR>\n" );
document.write( "120+2y=240<BR>\n" );
document.write( "2y=120<BR>\n" );
document.write( "y=60% solution B<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );