document.write( "Question 356953: A rectangle is twice as long as it is wide. If the width is increased by 25% and the length is decreased by 25%, the resulting rectangle will have 200 fewer square units of area than the original rectangle. What is the original width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #254895 by mananth(16946)\"\" \"About 
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A rectangle is twice as long as it is wide. If the width is increased by 25% and the length is decreased by 25%, the resulting rectangle will have 200 fewer square units of area than the original rectangle. What is the original width of the rectangle?
\n" ); document.write( "...
\n" ); document.write( "width be x
\n" ); document.write( "length be 2x
\n" ); document.write( "Area = x*2x=2x^2
\n" ); document.write( "..
\n" ); document.write( "width increase by 25% which means the width becomes 1.25x
\n" ); document.write( "length is decreased by 25% which means it becomes 0.75*2x=1.5x
\n" ); document.write( "Area = 1.25x*1.5x= 1.875x^2\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "2.0x^2 - 1.875x^2= 200
\n" ); document.write( "0.125x^2=200
\n" ); document.write( "x^2= 200/0.125
\n" ); document.write( "x^2=1600
\n" ); document.write( "x= 40 the width
\n" ); document.write( "length = 3x = 120 units
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\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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