document.write( "Question 356942: find cd and ef then determine if cd is congruent to ef \r
\n" ); document.write( "\n" ); document.write( "d is (-2,4)
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\n" ); document.write( "\n" ); document.write( "e is (2,2)
\n" ); document.write( "f is (5,-2
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Algebra.Com's Answer #254888 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, we need to find the length of cd. So we need to find the distance between (-5,0) and (-2,4).\r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=-5\" and \"y%5B1%5D=0\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=-2\" and \"y%5B2%5D=4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-5--2%29%5E2%2B%280-4%29%5E2%29\" Plug in \"x%5B1%5D=-5\", \"x%5B2%5D=-2\", \"y%5B1%5D=0\", and \"y%5B2%5D=4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-3%29%5E2%2B%280-4%29%5E2%29\" Subtract \"-2\" from \"-5\" to get \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-3%29%5E2%2B%28-4%29%5E2%29\" Subtract \"4\" from \"0\" to get \"-4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B%28-4%29%5E2%29\" Square \"-3\" to get \"9\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B16%29\" Square \"-4\" to get \"16\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2825%29\" Add \"9\" to \"16\" to get \"25\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=5\" Take the square root of \"25\" to get \"5\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=5\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is 5 units. \r
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\n" ); document.write( "\n" ); document.write( "So the length of cd is 5 units.\r
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\n" ); document.write( "\n" ); document.write( "Now we need to find the length of ef. So we need to find the distance between the points (2,2) and (5,-2)\r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=2\" and \"y%5B1%5D=2\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=5\" and \"y%5B2%5D=-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%282-5%29%5E2%2B%282--2%29%5E2%29\" Plug in \"x%5B1%5D=2\", \"x%5B2%5D=5\", \"y%5B1%5D=2\", and \"y%5B2%5D=-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-3%29%5E2%2B%282--2%29%5E2%29\" Subtract \"5\" from \"2\" to get \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-3%29%5E2%2B%284%29%5E2%29\" Subtract \"-2\" from \"2\" to get \"4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B%284%29%5E2%29\" Square \"-3\" to get \"9\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%289%2B16%29\" Square \"4\" to get \"16\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2825%29\" Add \"9\" to \"16\" to get \"25\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=5\" Take the square root of \"25\" to get \"5\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=5\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is also 5 units. \r
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\n" ); document.write( "\n" ); document.write( "So the length of ef is also 5 units.\r
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\n" ); document.write( "\n" ); document.write( "This means that cd and ef are congruent (since they are the same length).\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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