document.write( "Question 40066: HELP!!!
\n" ); document.write( "change the fraction w-3/w+5 into an equivalent fraction with the denominator \"w%5E2%2Bw-20\"
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Algebra.Com's Answer #25487 by tran3209(100)\"\" \"About 
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W^2 + W - 20 factor the expression: (W+5)(W-4)\r
\n" ); document.write( "\n" ); document.write( "W-3/W+5 to make the denominator become (W+5)(W-4) we need to multiply the \r
\n" ); document.write( "\n" ); document.write( "fraction by W-4/W-4\r
\n" ); document.write( "\n" ); document.write( "( W-3/W+5 )( W-4/W-4 )\r
\n" ); document.write( "\n" ); document.write( "(W-3)(W-4)/(W+5)(W-4)\r
\n" ); document.write( "\n" ); document.write( "W^2-7W+12/W^2+W-20\r
\n" ); document.write( "\n" ); document.write( "The answer is : W^2-7W+12/W^2+W-20
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