document.write( "Question 356825: Two buses leave a station at the same time, traveling in opposite directions. The rate of the slower bus is 15mph less than the rate of the faster bus. After 4 hours, they are 492 miles apart. What is the rate of the slower bus? \n" ); document.write( "
Algebra.Com's Answer #254848 by ankor@dixie-net.com(22740)\"\" \"About 
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Two buses leave a station at the same time, traveling in opposite directions.
\n" ); document.write( " The rate of the slower bus is 15mph less than the rate of the faster bus.
\n" ); document.write( " After 4 hours, they are 492 miles apart.
\n" ); document.write( " What is the rate of the slower bus?
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of the slower bus
\n" ); document.write( "then
\n" ); document.write( "(s+15) = speed of the faster bus
\n" ); document.write( ":
\n" ); document.write( "When they travel in opposite directions, the distances are added
\n" ); document.write( "Write a distance equation. Dist = time * speed
\n" ); document.write( ":
\n" ); document.write( "4s + 4(s+15) = 492
\n" ); document.write( "4s + 4s + 60 = 492
\n" ); document.write( "8s = 492 - 60
\n" ); document.write( "8s = 432
\n" ); document.write( "s = \"432%2F8\"
\n" ); document.write( "s = 54 mph is the rate of the slower bus
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the total distances (54+15=69mph is the faster bus)
\n" ); document.write( "4(69) = 276
\n" ); document.write( "4(54) = 216
\n" ); document.write( "--------------
\n" ); document.write( "total: 492 \n" ); document.write( "
\n" );