document.write( "Question 356890: Tickets at a park are $1.50 for kids and $4.00 for adults. On c certain day 2200 people entered the park, and the the admission fees collected totaled $5050. How many children and how many adults were admitted? \n" ); document.write( "
Algebra.Com's Answer #254840 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! x+y=2200 ------> y = 2200-x \n" ); document.write( "1.5x+4y=5050 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.5x+4y=5050 \n" ); document.write( "15x+40y=50500 \n" ); document.write( "15x+40(2200-x)=50500 \n" ); document.write( "15x+88000-40x=50500 \n" ); document.write( "-25x+88000=50500 \n" ); document.write( "-25x=50500-88000 \n" ); document.write( "-25x=37500 \n" ); document.write( "x=1500 ------> 1500 kids\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=2200-x=2200-1500 = 700 \n" ); document.write( "y = 700 ----> 700 adults \n" ); document.write( " |