document.write( "Question 356678: the perimeter of a rectangle is 48 feet.what is the dimensions of the rectangle if the length is 6 feet longer than twice the width? \n" ); document.write( "
Algebra.Com's Answer #254826 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "Let x represent the width and (2x+6) be the length. Now we can set up an equation:
\n" ); document.write( "2x + 2(2x+6)=48
\n" ); document.write( "Expand and combine like terms:
\n" ); document.write( "4x+14=48
\n" ); document.write( "Subtract 14 and divide by 4 each side to get:
\n" ); document.write( "x=4.5
\n" ); document.write( "So now we know the width is 4.5 feet and the length is 15 feet.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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