document.write( "Question 356678: the perimeter of a rectangle is 48 feet.what is the dimensions of the rectangle if the length is 6 feet longer than twice the width? \n" ); document.write( "
Algebra.Com's Answer #254826 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "Let x represent the width and (2x+6) be the length. Now we can set up an equation: \n" ); document.write( "2x + 2(2x+6)=48 \n" ); document.write( "Expand and combine like terms: \n" ); document.write( "4x+14=48 \n" ); document.write( "Subtract 14 and divide by 4 each side to get: \n" ); document.write( "x=4.5 \n" ); document.write( "So now we know the width is 4.5 feet and the length is 15 feet. \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "www.math-unlock.com \n" ); document.write( " \n" ); document.write( " |