document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39961>Question 39961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During an election campaign a candidate gave away 5000 little advertisements. The pens she gave away cost $.23 cents each and the little bumper stickers cost $.14 cents each. He spent a total of $970.00. How many pens did he give away?<BR>\n" );
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document.write( "thanx </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25479 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let p be the number of pens and b be the number of bumper stickers.<BR>\n" );
document.write( "Their costs are then .23p and .14b, respectively...so we have<BR>\n" );
document.write( "p + b = 5000<BR>\n" );
document.write( ".23p + .14b = 970<BR>\n" );
document.write( "We can combine these by a linear sum by multiplying the first equation by 14 and the second by 100...then we subtract the equations...we get<BR>\n" );
document.write( "14p + 14b = 70000<BR>\n" );
document.write( "-(23p + 14b = 97000)<BR>\n" );
document.write( "and get<BR>\n" );
document.write( "-9p = - 27000<BR>\n" );
document.write( "p = 3000<BR>\n" );
document.write( "Thus he/she gave away 3000 pens and 2000 bumper stickers. </SPAN>\n" );
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