document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40010>Question 40010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jar of dimes and quarters contained $10.95 There were at 93 coins in the jar. How many dimes?<BR>\n" );
document.write( " thanx </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25476 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d be the number of dimes and q will be quarters.<BR>\n" );
document.write( "Their values will be 10d and 25q respectively.  So we have<BR>\n" );
document.write( "d + q = 93<BR>\n" );
document.write( "10d + 25q = 1095  (talking about cents now)<BR>\n" );
document.write( "We can do a linear sum of these by multiplying the first equation by 25 and subtracting...so we get<BR>\n" );
document.write( "10d + 25q = 1095<BR>\n" );
document.write( "-(25d + 25q = 2325)<BR>\n" );
document.write( "and we have<BR>\n" );
document.write( "-15d = -1230<BR>\n" );
document.write( "d = 82<BR>\n" );
document.write( "Thus there are 82 dimes and 11 quarters. </SPAN>\n" );
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