document.write( "Question 356836: The perimeter of a rectangle is 64cm. Twice the width is 4cm more than the length. Find the dimensions.\r
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\n" ); document.write( "\n" ); document.write( "I don't understand how to do it. If you could show me some steps that'd be great.
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Algebra.Com's Answer #254756 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "Let the length is x cm and width is y cm.\r
\n" ); document.write( "\n" ); document.write( "then perimeter 2(x+y) =64 cm\r
\n" ); document.write( "\n" ); document.write( "=> x+y = 64/2 = 32\r
\n" ); document.write( "\n" ); document.write( "=> x + y = 32 .............(1)\r
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\n" ); document.write( "\n" ); document.write( "and according to question twice the width is 4cm more than length so,\r
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\n" ); document.write( "\n" ); document.write( "2y = x + 4 \r
\n" ); document.write( "\n" ); document.write( "=> 2y -x = 4 .............(2)\r
\n" ); document.write( "\n" ); document.write( "now we add these two equation to find the value of x and y.\r
\n" ); document.write( "\n" ); document.write( "3y = 36 \r
\n" ); document.write( "\n" ); document.write( "=> y = 12 \r
\n" ); document.write( "\n" ); document.write( "now put the value of y on any equation to find value of x ,\r
\n" ); document.write( "\n" ); document.write( " x +12 = 32 \r
\n" ); document.write( "\n" ); document.write( "=> x = 32 -12 = 20 \r
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\n" ); document.write( "\n" ); document.write( "so length is 20cm and width is 12cm.
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