document.write( "Question 40032: Bob has 3000 feet of fencing available to enclose a rectangular field.
\n" ); document.write( "A. express the area A of rectangle as a function of x where x is the length of rectangle.
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\n" ); document.write( "C. what is the maximum area?
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Algebra.Com's Answer #25475 by venugopalramana(3286)\"\" \"About 
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> 2. Bob has 3000 feet of fencing available to enclose a rectangular field.
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\n" ); document.write( "> a. express the area A of rectangle as a function of x where x is the length
\n" ); document.write( "> of rectangle.
\n" ); document.write( "L=X...PERIMETER=L+B+L+B=2(L+B)=2(X+B)=3000
\n" ); document.write( "X+B=1500
\n" ); document.write( "B=1500-X
\n" ); document.write( "AREA =A= L*B=X(1500-X)
\n" ); document.write( "> b. for what value of x is the area largest?
\n" ); document.write( "A=X(1500-X)=-(X^2-1500X)=-(X^2-2*X*750+750^2)+750^2
\n" ); document.write( " A=750^2-(X-750)^2
\n" ); document.write( "HENCE THIS WILL BE MAXIMUM WHEN X=750
\n" ); document.write( "> c. what is the maximum area.
\n" ); document.write( "> MAXIMUM AREA =750^2-0=750^2=562500
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