document.write( "Question 40039: Please help me with these three problems.\r
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document.write( " 1. Find the solution to the equation log(x)8=1/3.\r
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document.write( " 2. Find the approximate solution to the equation 3(1.5^x)+10=280.\r
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document.write( " 3. Find the solution to the equation 2 log(a)3 + log(a)(x-4)= log(a)(x+8).\r
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document.write( " () below the log\r
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document.write( "Thank you very much.\r
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document.write( "Chris \n" );
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Algebra.Com's Answer #25474 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! 1) log(x)8 = 1/3 \n" ); document.write( "Change this into an exponential form first and then solve, so we get \n" ); document.write( "x^(1/3) = 8 \n" ); document.write( "x = 8^3 = 512\r \n" ); document.write( "\n" ); document.write( "2) 3(1.5^x) + 10 = 280 \n" ); document.write( "Here isolate the exponential first and get \n" ); document.write( "3(1.5^x) = 270 \n" ); document.write( "1.5^x = 90 \n" ); document.write( "Now take the log \n" ); document.write( "x*log(1.5) = log(90) \n" ); document.write( "x = log(90) / log(1.5)\r \n" ); document.write( "\n" ); document.write( "3) 2*log(a)3 + log(a)(x-4) = log(a)(x+8) \n" ); document.write( "Combine the left hand side first \n" ); document.write( "log(a) [3^2*(x-4)] = log(a)(x+8) so that \n" ); document.write( "9(x - 4) = x + 8 \n" ); document.write( "9x - 36 = x + 8 \n" ); document.write( "8x = 44 \n" ); document.write( "x = 11/2 \n" ); document.write( " |