document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39938>Question 39938</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130442631/algebrahomeworkh>alegbra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> whats the square root of 3y over x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25468 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have to rationalize the denominator of sqrt(3y/x) by multiplying by sqrt(x) over itself...thus we get<BR>\n" );
document.write( "sqrt(3y/x) * sqrt(x)/sqrt(x) = <BR>\n" );
document.write( "sqrt(3y)/sqrt(x)  * sqrt(x)/sqrt(x) = <BR>\n" );
document.write( "sqrt(3xy) / x </SPAN>\n" );
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