document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356726>Question 356726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What weight must be added to 50g of 36% sulfuric acid solution to yield a 20% solution? All percents are weight. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254657 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # grams of water that has to be added.  Then <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50%2A0.36+%2B+x%2A0+=+%2850+%2B+x%29%2A0.20 ALIGN=MIDDLE  ALT=\"50%2A0.36+%2B+x%2A0+=+%2850+%2B+x%29%2A0.20\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=18+=+10+%2B+0.20x ALIGN=MIDDLE  ALT=\"18+=+10+%2B+0.20x\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8+=+0.20x ALIGN=MIDDLE  ALT=\"8+=+0.20x\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40+=+x ALIGN=MIDDLE  ALT=\"40+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Therefore 40 grams of water has to be added. </SPAN>\n" );
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