document.write( "Question 40038: Assume that a ball is thrown vertically upward with initial velocity fo 96 ft per second. The distance s(t) (in feet) of the ball from the ground after t seconds is s(t)=96t-16t^2.
\n" ); document.write( "a. at what instant will it be back at the ground level?
\n" ); document.write( "b. for what time interval is the ball more than 112ft above the ground?
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Algebra.Com's Answer #25465 by venugopalramana(3286)\"\" \"About 
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SEE THE FOLLOWING EXAMPLE WHICH IS SIMILAR TO YOURS AND TRY.
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\n" ); document.write( " 1. Assume that a ball is thrown vertically upward with initial velocity of
\n" ); document.write( "> 96 ft. per second. The distance s(t) (in feet) of the ball from the ground
\n" ); document.write( "> after t seconds is s(t) = 96t-16t^2.
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\n" ); document.write( "> a. at what instant will it be back at the ground level?
\n" ); document.write( "AT GROUND S=0=96T-16T^2=16T(T-9)
\n" ); document.write( "HENCE T=0 ..THAT IS BEFORE IT IS THROWN UP AND
\n" ); document.write( "T=9...SO AFTER 9 SECS.IT WILL HIT THE GROUND ON FALL\r
\n" ); document.write( "\n" ); document.write( "> b. for what time interval is the ball more than 128 ft. above the ground.
\n" ); document.write( "> S=128=96T-16T^2.DIVIDING BY 16
\n" ); document.write( "T^2-6T+8=0=T^2-4T-2T+8=T(T-4)-2(T-4)=(T-4)(T-2)=0
\n" ); document.write( "T=2 SECS ON THE UPWARD TRAVEL AND
\n" ); document.write( " T=4 SECS ON THE DOWNWARD TRAVEL.HENCE IT WILL BE OVER 128 FT.HIGH
\n" ); document.write( "DURING T=2 TO 4 SECS.
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