document.write( "Question 356716: A rectangle is 4 m longer than it is wide. If the lenght and width are both increased by 5 m, the are is increased by 115 m squared. Find the original dimensions. \n" ); document.write( "
Algebra.Com's Answer #254634 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A rectangle is 4 m longer than it is wide. If the lenght and width are both increased by 5 m, the are is increased by 115 m squared. Find the original dimensions. \n" ); document.write( "... \n" ); document.write( "let width be x \n" ); document.write( "length = x+4 \n" ); document.write( "Area = x(x+4) \n" ); document.write( "... \n" ); document.write( "increased by 5 \n" ); document.write( "width x+5 \n" ); document.write( "length = x+4+5 = x+9 \n" ); document.write( "Area = (x+5)(x+9) \n" ); document.write( "... \n" ); document.write( "(x+5)(x+9)-x(x+4) =115 \n" ); document.write( "x^2+14x+45-x^2-4x=115 \n" ); document.write( "10x+45=115 \n" ); document.write( "10x=115-45 \n" ); document.write( "10x=70 \n" ); document.write( "x=7 the width \n" ); document.write( "length = 11\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |