document.write( "Question 356716: A rectangle is 4 m longer than it is wide. If the lenght and width are both increased by 5 m, the are is increased by 115 m squared. Find the original dimensions. \n" ); document.write( "
Algebra.Com's Answer #254634 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
A rectangle is 4 m longer than it is wide. If the lenght and width are both increased by 5 m, the are is increased by 115 m squared. Find the original dimensions.
\n" ); document.write( "...
\n" ); document.write( "let width be x
\n" ); document.write( "length = x+4
\n" ); document.write( "Area = x(x+4)
\n" ); document.write( "...
\n" ); document.write( "increased by 5
\n" ); document.write( "width x+5
\n" ); document.write( "length = x+4+5 = x+9
\n" ); document.write( "Area = (x+5)(x+9)
\n" ); document.write( "...
\n" ); document.write( "(x+5)(x+9)-x(x+4) =115
\n" ); document.write( "x^2+14x+45-x^2-4x=115
\n" ); document.write( "10x+45=115
\n" ); document.write( "10x=115-45
\n" ); document.write( "10x=70
\n" ); document.write( "x=7 the width
\n" ); document.write( "length = 11\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" );