document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356609>Question 356609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle box with a base 6 by 8 has a diagonal of length 20. Find the exact height of the box. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254629 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6^2+8^2<BR>\n" );
document.write( "=36+64<BR>\n" );
document.write( "=100<BR>\n" );
document.write( "sqrt(100)=10 diagonal of the base of the box.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "hypotenuse=20 given. Goes from the base of one corner to the top of the other corner.<BR>\n" );
document.write( "a^2+10^2=20^2<BR>\n" );
document.write( "a^2+100=400<BR>\n" );
document.write( "a^2=300<BR>\n" );
document.write( "a=sqrt(300)<BR>\n" );
document.write( "=sqrt(100*3)<BR>\n" );
document.write( "=10sqrt(3) exact height of box.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );